I have created a search form with RSForm Pro, unfortunately it isn't working.

The concept is to do a TAG Search all the Fields of the Form (Select and Radio) have values which are part of a URL which has to be build when you press on "suchen" (Fields are depending on each other and the button will only show up when all steps have been completed).

I am using this code trying to accomplish this:

function suchen() {
    var URLBase = "http://ego.pc-helfer.eu/index.php?option=com_tags&view=tag";
    var TrailingFixedData = "&types[0]=1";

    finalURL = URLBase + document.getElementsByClassName('value1').value +
    document.getElementsByClassName('value2').value +         
    document.getElementsByClassName('value3').value + 
    document.getElementsByClassName('value4').value + 
    document.getElementsByClassName('value5').value + TrailingFixedData;

But when I press "suchen" the Chrome console tells me:

Uncaught ReferenceError: suchen is not defined

I can see the script is being loaded, but I still get this message.

url of the site: http://ego.pc-helfer.eu/produktsuche/substrattkompass

  • FYI document.getElementsByClassName returns a NodeList object. Perhaps you need to write something like this: document.getElementsByClassName('value1')[0].value
    – Farahmand
    Aug 29 '14 at 12:04

Remove onclick="suchen()" and use these lines of code:

<script type="text/javascript">
jQuery(document).ready(function() {
    jQuery('#Suchen').on('click', function() {
        // Your Code Here.
  • Nice got it to work, although at first it didn't work with document.getElementsByClassName so i had to switch to document.getElementById. Now the URL is being build properly. Now the main issue is that i don't want the form to be reset. So i will probably have to make an Ajax request or isn't this possible?
    – Hyperxx
    Aug 30 '14 at 9:22
  • AJAX is an option. Another option is to fill the form from URL parameters via javascript or jQuery after the page is loaded. Another option is to create a plugin and fill the form in server side. You will need to write a javascript function to show all parts of the form.
    – Farahmand
    Aug 30 '14 at 10:22

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