I have created a custom user field named "Gender".

How can I show this field in an article?

I can only manage to show: username, name, email and User Id

Here is my current Sourcerer code to access the username:

{source} <?php $user = JFactory::getUser(); echo $user->get('name'); {/source}
  • Have you found any tutorials? Checked the Joomla documentation? Found any pre-existing pages here on JSE? Do you have any coding attempts to share? Oct 12, 2018 at 0:21
  • Do you want this gender data to be displayed on all Articles or just one? If all, then perhaps a template override would be simplest. Can you explain how and why you are adding this data to your article (this gives your question context). Oct 12, 2018 at 0:42
  • if i want to display user name i use {source} <?php $user = JFactory::getUser(); echo $user->get('name'); {/source} how about user field like Gender? Nov 12, 2018 at 14:59
  • i just need to display it only on some pages as pages are restricted depending on groups allocated to users Nov 12, 2018 at 15:01
  • What is the identifying column (field_id) value for your gender data in #__fields_values? Nov 12, 2018 at 23:23

1 Answer 1


Okay, I'll explain by using a fictitious value.

You will need to reference the #__users table and the #__fields_values table.

Assuming you are only dealing with logged in users, you will need to acquire the user's id via JFactory::getUser()->id.

Then you will need to know the field_id that the gender value is stored with in the #__fields_values table. For my example below I'll use 28 as the field_id value; if you don't know what the correct field_id value is for your project, you can search for it in the #__fields table the integer that you need to source is in the id column.

By performing an INNER JOIN on the two tables, using two conditions in the WHERE clause and calling for a single value in the result set via loadResult(), you shall have your gender value.

try {
    $db = JFactory::getDbo();
    $user_id = JFactory::getUser()->id;
    $query = $db->getQuery(true)
        ->select("b.value AS gender")
        ->from("#__users a")
        ->innerJoin("#__fields_values b ON a.id = b.item_id")
        ->where(["b.field_id = 28", "b.item_id = " . (int)$user_id]);  // $user_id should already be an integer, but cast to be extra safe
    // JFactory::getApplication()->enqueueMessage($query->dump(), 'info');
    if (!$gender = $db->loadResult()) {
        echo "<p>No Value Found</p>";
    } else {
        echo "<p>$gender</p>";
} catch (Exception $e) {
    JFactory::getApplication()->enqueueMessage("Query Syntax Error: " . $e->getMessage(), 'error');  // don't show $e->getMessage() to public

p.s. if you don't want to hardcode the "28" into your query, you can perform a dynamic lookup of the number, but that will require another JOIN with the #__fields table -- this is not likely to worth the effort in most cases.

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